老何快来看， Mathematical Proof that 1=0

[TIFF]

Given that a and b are integers such that a = b + 1,
Prove: 1 = 0

1. a = b + 1 (Given)

2. (a-b)a = (a-b)(b+1) (Multiplication Prop. of =)

3. a2 – ab = ab + a – b2 – b (Distributive Property)

4. a2 – ab -a = ab + a -a – b2 – b (Subtraction Prop. of =)

5. a(a – b – 1) = b(a – b – 1) (Distributive Property)

6. a = b (Division Property of = )

7. b + 1 = b (Transitive Property of = (Steps 1, 7) )

8. Therefore, 1 = 0 (Subtraction Prop. of =)

 

[heureux]

这个题目本来就是我出的，现在满世界转了一圈又转回来了

 

[TIFF]

才转到我这儿来。

 

[colonel]

a-b-1=0

so step 5 is wrong

divide by 0

 

[fyc_zx]

a-b-1=0. 不能两边同除以0.

 

[冷笑六声]

 

[TIFF]

Yes, you are correct.

 

[playgo]

踢老师，你到底是教什么课的？EE，编程还是数学？

 

[大熊猫]

LZ，逗老何玩呢？

 

[heureux]

LZ，逗老何玩呢？

我一见你就笑，你这头像太奇妙

 

[扣 扣]

何总，我在音乐城里存的歌不动欢了～～:blowzy:

突然好多都变成这样了～～

[ame="http://www.youtube.com/watch?v=p0mII6cMGpA"]THE HATS INSPIRED QUEEN OF THE 70'S....Fong Fei Fei....wmv - YouTube[/ame]

 

[ccc]

何总，我在音乐城里存的歌不动欢了～～:blowzy:

没睡醒呢。

 

[扣 扣]

没睡醒呢。

怎么回事啊～～

 

[苦逼热狗]

4. a2 – ab -a = ab + a -a – b2 – b (Subtraction Prop. of =)
5. a(a – b – 1) = b(a – b – 1) (Distributive Property)
hmmm
a(2-b-1)=b(a-2-1)
a(1-b)=b(a-1)

 

[扣 扣]

没睡醒呢。

新上的可以。以前的怎么突然爆了，我也没有动过～～