论证题

[S_B_LogyBear]

欢迎大家来证明：

LogyBear不是S...B...

特设三等奖三名，二等奖二名，一等奖一名。分别奖励CFC币$3000，$2000和$1000。

 

[calculus]

最初由 S_B_LogyBear 发布
欢迎大家来证明：

LogyBear不是S...B...

特设三等奖三名，二等奖二名，一等奖一名。分别奖励CFC币$3000，$2000和$1000。

because: Logy!=S Bear=B
thus: LogyBear != SB
proven~

 

[空号]

"特设三等奖三名，二等奖二名，一等奖一名。分别奖励CFC币$3000，$2000和$1000"

按次序来，应该是三个三等奖一共给3K（没说每人3千）

2个2等奖一共2K。

1个1等奖1K。。

这帐算的这个精啊。。1等2等3等给的一样多。。。这么精明地东东，怎么能是SB呢？

论证完毕。。（看着给吧）

 

[S_B_LogyBear]

But...

because: Logy=Sluggish, Bear=B
thus: LogyBear=SB

 

[calculus]

最初由 S_B_LogyBear 发布
But...

because: Logy=Sluggish, Bear=B
thus: LogyBear=SB

prove by contridiction, not induction~

 

[不乖de宝宝]

这个................

 

[瑞=风]

LogyBear不是S...B...

logy=迟缓的, 呆呆的 bear=1,熊

s=super b=boy 所以可证 呆呆熊 not= super boy

 

[小吱]

我不明白,谁给我讲讲啊~~~

 

[calculus]

最初由 麻仓雅典娜 发布
我不明白,谁给我讲讲啊~~~

嗯~等你在学深点吧~:blink:

 

[小吱]

最初由 jyhua29 发布

嗯~等你在学深点吧~:blink:

你说什么!!!!!!!!!!!!!!!:flaming: :flaming: :flaming: :flaming:

 

[zaizai]

because: Logy=Slow, Bear=B
thus: LogyBear=SB

 

[文 武]

log base y of B <=> y^? = B

? * e^ar = x (lower case)

? = X (upper case) /(e^ar)

--> X = B (傻X)

--> ? = B / e^ar

where B = constant
e = lim as h -> 1 (e^h-1)/h = 1
a = antimony
r = radius of a circle

---> antimony = Sb
---> ? = B / e^(Sb * r)
---> B has no effect
--->? = e^(Sb * r)

--> ln ? = ln e^(Sb * r)
ln ? = Sb * r ln e
ln ? = Sb * r
--> r is a constant thus has no effect,
ln ? = Sb or ln ? = SB

-> ln ? = constant = c
therefore c = 3 (alphabetical order)

-> S = 19, B= 2, SB = 38

since 38 is not equal to 2, therefore LogyBear is not equal to SB.

 

[华华再生]

晕倒...................

最初由 文 武 发布
log base y of B <=> y^? = B

? * e^ar = x (lower case)

? = X (upper case) /(e^ar)

--> X = B (傻X)

--> ? = B / e^ar

where B = constant
e = lim as h -> 1 (e^h-1)/h = 1
a = antimony
r = radius of a circle

---> antimony = Sb
---> ? = B / e^(Sb * r)
---> B has no effect
--->? = e^(Sb * r)

--> ln ? = ln e^(Sb * r)
ln ? = Sb * r ln e
ln ? = Sb * r
--> r is a constant thus has no effect,
ln ? = Sb or ln ? = SB

-> ln ? = constant = c
therefore c = 3 (alphabetical order)

-> S = 19, B= 2, SB = 38

since 38 is not equal to 2, therefore LogyBear is not equal to SB.

 

[瑞=风]

牛

 

[UW2003 Rev1]

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