文 武 Moderator 管理成员 注册 2003-09-05 消息 10,679 荣誉分数 0 声望点数 0 2004-05-05 #1 the relationship between the rate of change of radius, surface area and volume of a sphere -------------------------->RELATIONSHIP between dr/dt, dS/dt and dV/dt ---------------> with respect to time
the relationship between the rate of change of radius, surface area and volume of a sphere -------------------------->RELATIONSHIP between dr/dt, dS/dt and dV/dt ---------------> with respect to time
文 武 Moderator 管理成员 注册 2003-09-05 消息 10,679 荣誉分数 0 声望点数 0 2004-05-05 #4 tell me the answer, i got a page of relationships, still ,tell me more
J jackywyy 初级会员 注册 2003-05-17 消息 13,690 荣誉分数 1 声望点数 0 2004-05-05 #6 r = radius S = 4(pi)r^2 V = 4/3 (pi)r^3
J jackywyy 初级会员 注册 2003-05-17 消息 13,690 荣誉分数 1 声望点数 0 2004-05-05 #8 phys? I need more info about what you want
J jackywyy 初级会员 注册 2003-05-17 消息 13,690 荣誉分数 1 声望点数 0 2004-05-05 #9 r as a function of t sub r=f(t) into S(r) and V(r) then you got S(t) and V(t) take first order differentiaion of S(t) and V(t) ---------------> dS/dt and dV/dt
r as a function of t sub r=f(t) into S(r) and V(r) then you got S(t) and V(t) take first order differentiaion of S(t) and V(t) ---------------> dS/dt and dV/dt
J jackywyy 初级会员 注册 2003-05-17 消息 13,690 荣誉分数 1 声望点数 0 2004-05-05 #10 or you can do dS/dt = dS/dr x dr/dt dV/dt = dV/dr x dr/dt
~~LORD~~ 开坛元勋--少奶奶 注册 2004-03-11 消息 5,463 荣誉分数 3 声望点数 0 2004-05-05 #11 楼主, 你也没交ASSIGNMENT啊.. 我今天下课的时候跑得太快了,忘了交ASSIGNMENT
