~~LORD~~ 开坛元勋--少奶奶 注册 2004-03-11 消息 5,463 荣誉分数 3 声望点数 0 2004-06-15 #3,076 for vertical asymptote, let the denominator equal to zero, then solve for x
~~LORD~~ 开坛元勋--少奶奶 注册 2004-03-11 消息 5,463 荣誉分数 3 声望点数 0 2004-06-15 #3,078 for horizontal asymptote, see the end behavior of f(x) as x approaches +/- infinite
~~LORD~~ 开坛元勋--少奶奶 注册 2004-03-11 消息 5,463 荣誉分数 3 声望点数 0 2004-06-15 #3,079 I'll protect myself... 这世道, 靠不上别人... for oblique asymptote, divide the numerator by the denominator... then ignore the remainder.
I'll protect myself... 这世道, 靠不上别人... for oblique asymptote, divide the numerator by the denominator... then ignore the remainder.
NAN_BO_ONE 就是NAN_BO_ONE 注册 2004-05-20 消息 3,283 荣誉分数 0 声望点数 0 2004-06-15 #3,080 最初由 难波万 发布 难道就没人保护MLY? 点击展开... me 是护花使者
文 武 Moderator 管理成员 注册 2003-09-05 消息 10,679 荣誉分数 0 声望点数 0 2004-06-15 #3,081 最初由 萝卜Q 发布 I'll protect myself... 这世道, 靠不上别人... for oblique asymptote, divide the numerator by the denominator... then ignore the remainder. 点击展开... i thought you had friends~~~~~~~~~~~
最初由 萝卜Q 发布 I'll protect myself... 这世道, 靠不上别人... for oblique asymptote, divide the numerator by the denominator... then ignore the remainder. 点击展开... i thought you had friends~~~~~~~~~~~
~~LORD~~ 开坛元勋--少奶奶 注册 2004-03-11 消息 5,463 荣誉分数 3 声望点数 0 2004-06-15 #3,082 as for the limits of a fnct, we can use a chart or substitute...
文 武 Moderator 管理成员 注册 2003-09-05 消息 10,679 荣誉分数 0 声望点数 0 2004-06-15 #3,083 最初由 NAN_BO_ONE 发布 me 是护花使者 点击展开... cao cao cao ~~~~~~~~~~`bu xing le, buxing le~~~~~~~~`
难波万 新手上路 注册 2003-11-23 消息 1,997 荣誉分数 0 声望点数 0 2004-06-15 #3,084 最初由 NAN_BO_ONE 发布 me 是护花使者 点击展开... 快把她从这帖子里拉出去~~小心被人:kill:
~~LORD~~ 开坛元勋--少奶奶 注册 2004-03-11 消息 5,463 荣誉分数 3 声望点数 0 2004-06-15 #3,085 最初由 NAN_BO_ONE 发布 me 是护花使者 点击展开... ...
~~LORD~~ 开坛元勋--少奶奶 注册 2004-03-11 消息 5,463 荣誉分数 3 声望点数 0 2004-06-15 #3,086 and continuous fnct, jump discont., removable discont.(where the discontinuity can be removed by factoring)
and continuous fnct, jump discont., removable discont.(where the discontinuity can be removed by factoring)
~~LORD~~ 开坛元勋--少奶奶 注册 2004-03-11 消息 5,463 荣誉分数 3 声望点数 0 2004-06-15 #3,088 critera for continuity, f(a) exist, lim as x approaches a exist, f(a)=limf(x)