几何题求解. 若给出正确答案,俺请吃饭,俺请吃饭!

最初由 GreenGable 发布
由于两个一组的正三角形的稳定作用, 可以想象成相邻的四方形外角有一条连接线, 且线段长不变.

如果要使四方形变形,此线段长度将改变.

this is not true :D

denial on both :D
 
最初由 Isabel 发布

:)
谢谢你的图! VISIO,俺一定好好学学!

之前,俺用元规,直尺画了下图:
 
最初由 heureux 发布

谢谢你的图! VISIO,俺一定好好学学!

之前,俺用元规,直尺画了下图:

尺规作图,楼主很有钻研精神啊!
 
最初由 lavie 发布

尺规作图,楼主很有钻研精神啊!
俺的废纸篓子里有一小堆这样的图!
 
上面那个3,4,5的脚手架共用了 49 块辅助木板使正方形稳定。

目前所能做到的最好答案是用 23 块辅助木板:
 
最初由 heureux 发布
上面那个3,4,5的脚手架共用了 49 块辅助木板使正方形稳定。

目前所能做到的最好答案是用 23 块辅助木板:

我怎么觉得如果同时从上下两点用力,图形会变扁呢?还有,证明那个角是直角了吗?
 
最初由 lavie 发布


我怎么觉得如果同时从上下两点用力,图形会变扁呢?还有,证明那个角是直角了吗?
俺看这个图看了几天了,开始也这么想的。

但可以证明这个正方形是稳定的!
 
该往高层次带人了....

4.4.1 Gruebler's Equation

The definition of the degrees of freedom of a mechanism is the number of independent relative motions among the rigid bodies. For example, Figure 4-11 shows several cases of a rigid body constrained by different kinds of pairs.

Figure 4-11 Rigid bodies constrained by different kinds of planar pairs

In Figure 4-11a, a rigid body is constrained by a revolute pair which allows only rotational movement around an axis. It has one degree of freedom, turning around point A. The two lost degrees of freedom are translational movements along the x and y axes. The only way the rigid body can move is to rotate about the fixed point A.

In Figure 4-11b, a rigid body is constrained by a prismatic pair which allows only translational motion. In two dimensions, it has one degree of freedom, translating along the x axis. In this example, the body has lost the ability to rotate about any axis, and it cannot move along the y axis.

In Figure 4-11c, a rigid body is constrained by a higher pair. It has two degrees of freedom: translating along the curved surface and turning about the instantaneous contact point.

In general, a rigid body in a plane has three degrees of freedom. Kinematic pairs are constraints on rigid bodies that reduce the degrees of freedom of a mechanism. Figure 4-11 shows the three kinds of pairs in planar mechanisms. These pairs reduce the number of the degrees of freedom. If we create a lower pair (Figure 4-11a,b), the degrees of freedom are reduced to 2. Similarly, if we create a higher pair (Figure 4-11c), the degrees of freedom are reduced to 1.

Figure 4-12 Kinematic Pairs in Planar Mechanisms

Therefore, we can write the following equation:


F=3(n-1)-2l-h (4-1)

Where

F = total degrees of freedom in the mechanism
n = number of links (including the frame)
l = number of lower pairs (one degree of freedom)
h = number of higher pairs (two degrees of freedom)

This equation is also known as Gruebler's equation.
 
Where is your Figure 4-11?
 
哦,here-u-go, 刚才没对于拷上.
这应该是一个终极判断方法,以后对于一个平面图就不用几何证明是否稳定了.呵呵.
 
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